√ダウンロード p(x)=x^3-3x^2-x+p 265359-How to find p(x 3)
P(X 1 < X 2 < X 3) = triple integral of e(x 1 x 2 x 3) dx 2 dx 1 dx 3 as x 2 goes from x 1 to x 3, x 1 goes from 0 to x 2 and x 3 goes from x 2 to infinity When I solve this integral I get 0 for an answer The back of the book suggests the answer is 1/6 Clearly, I am setting up the problem wrong, but I don't know where my mistake isThe conditional probability P ( Y ≤ 075 X = 05 ) cannot be interpreted as P ( Y ≤ 075, X = 05 ) / P ( X = 05 ), since the latter gives 0/0 Accordingly, P ( Y ≤ 075 X = 05 ) cannot be interpreted via empirical frequencies, since the exact value X = 05 has no chance to appear at random, not even once during an infinite sequenceP (x) is divisible by x means (x) is a factor of p => 15 5k = 0 k = 3 If k = 3, p (x) = 3x^2 25x 15 5k Check k = 3 p (x) = 3x^2 25x p (x) = x (3x 25) => p (x) is divisible by x Edit it is easier if you find p (x=0) and make it equal to zero, then solve it for k Find The Values Of P And Q If The Polynomial G X X 2 3x 10 Is